Python Tutorial | Python tuples 3

Slicing

We can access a range of items in a tuple by using the slicing operator – colon “:”.

Example:

n=(‘c’,’o’,’m’,’p’,’u’,’t’,’e’,’r’)

Positive index

Negative index

n=(‘c’,’o’,’m’,’p’,’u’,’t’,’e’,’r’)
print(n)
print(n[0:2])
print(n[3:6])
print(n[6:7])
print(n[2:4])
print(n[:4])
print(n[4:])

output:

(‘c’, ‘o’, ‘m’, ‘p’, ‘u’, ‘t’, ‘e’, ‘r’)
(‘c’, ‘o’)
(‘p’, ‘u’, ‘t’)
(‘e’,)
Note: if there is only one element in the output then we will have “,” end the end of tuple output.

(‘m’, ‘p’)
(‘c’, ‘o’, ‘m’, ‘p’)
(‘u’, ‘t’, ‘e’, ‘r’)

n=('c','o','m','p','u','t','e','r')
print(n)
print(n[0:2])
print(n[3:6])
print(n[6:7])
print(n[2:4])
print(n[:4])
print(n[4:])

Output:

('c', 'o', 'm', 'p', 'u', 't', 'e', 'r')
('c', 'o')
('p', 'u', 't')
('e',)
('m', 'p')
('c', 'o', 'm', 'p')
('u', 't', 'e', 'r')
>>> 

Solve:

Example:
n=(‘c’,’a’,’t’,’a’,’l’,’y’,’s’,’t’)
print(n)
print(n[1:5])
print(n[6:7])
print(n[2:6])
print(n[7:])
print(n[3:6])
print(n[:5])
print(n[5:])

Slicing with negative index

n=(‘c’,’a’,’t’,’a’,’l’,’y’,’s’,’t’)

positive index

Negative index

n=(‘c’,’a’,’t’,’a’,’l’,’y’,’s’,’t’)
print(n)
#(‘c’, ‘a’, ‘t’, ‘a’, ‘l’, ‘y’, ‘s’, ‘t’)

print(n[-5:-3])
#(‘a’, ‘l’)

print(n[-5:-2])
#(‘a’, ‘l’, ‘y’)

print(n[2:6])
#(‘t’, ‘a’, ‘l’, ‘y’)

print(n[-7:])
#(‘a’, ‘t’, ‘a’, ‘l’, ‘y’, ‘s’, ‘t’)

print(n[-6:-4])
#(‘t’, ‘a’)

print(n[:-5])
#(‘c’, ‘a’, ‘t’)

print(n[-5:])
#(‘a’, ‘l’, ‘y’, ‘s’, ‘t’)

Solve:

n=(1,2,3,4,5,6,7,8,9,10)
print(n)
print(n[0:2])
print(n[3:6])
print(n[6:7])
print(n[2:4])
print(n[:4])
print(n[4:])

Solve:

n=(1,2,3,4,5,6,7,8,9,10)
print(n)
print(n[0:-2])
print(n[-6:-3])
print(n[-7:-5])
print(n[-4:-2])
print(n[:-4])
print(n[-4:])