Python program to check number is +ve or not.

Solution with out using functions
Solution using functions without passing arguments
Solution using functions and by passing arguments

Solution : Without using function
Program/Source Code

For better understanding of this example, one should have the knowledge of the following Python programming topics:

Python if…else… Statement
Python if…else…if…else… Statement
Python if…elif…if…elif…else… Statement

Program to check number is +ve ot not

n=int(input("Enter any number "))
if(n>0):
    print("Number is +ve")
else:
    print("Number is not +ve")

Try The Code

Output:

case 1:
Enter any number 95
Number is +ve
>>>
case 2:
Enter any number -45
Number is not +ve
>>>

Solution : Using function Without Passing Arguments
Program/Source Code

#function definition
def check():
    n=int(input("Enter any number "))
    if(n>0):
        print("Number is +ve")
    else:
        print("Number is not +ve")

#function calling
check()

Output:

case 1:
Enter any number 25
Number is +ve
>>>
case 2:
Enter any number -54
Number is not +ve
>>>

Solution : Using function Passing Arguments
Program/Source Code

#function definition
def check(n):
    if(n>0):
        print("Number is +ve")
    else:
        print("Number is not +ve")

#function calling
n=int(input("Enter any number "))
check(n)

Output:

case 1:
Enter any number 6
Number is +ve
>>>
case 2:
Enter any number -9
Number is not +ve
>>>

 

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