16.
What will be the output of the program?
#include<stdio.h>
int main()
{
int k, num = 30;
k = (num < 10) ? 100 : 200;
printf(“%d\n”, num);
return 0;
}
A. 200
B. 30
C. 100
D. 500
Answer: Option B
17.
What will be the output of the program?
#include<stdio.h>
int main()
{
int a = 300, b, c;
if(a >= 400)
b = 300;
c = 200;
printf(“%d, %d, %d\n”, a, b, c);
return 0;
}
A. 300, 300, 200
B. Garbage, 300, 200
C. 300, Garbage, 200
D. 300, 300, Garbage
Answer: Option C
Explanation:
Step 1: int a = 300, b, c; here variable a is initialized to ‘300’, variable b and c are declared, but not initialized.
Step 2: if(a >= 400) means if(300 >= 400). Hence this condition will be failed.
Step 3: c = 200; here variable c is initialized to ‘200’.
Step 4: printf(“%d, %d, %d\n”, a, b, c); It prints “300, garbage value, 200”. because variable b is not initialized.
18.
What will be the output of the program?
#include<stdio.h>
int main()
{
int x=1, y=1;
for(; y; printf(“%d %d\n”, x, y))
{
y = x++ <= 5;
}
printf(“\n”);
return 0;
}
A. 2 1
3 1
4 1
5 1
6 1
7 0
B. 2 1
3 1
4 1
5 1
6 1
C. 2 1
3 1
4 1
5 1
D. 2 2
3 3
4 4
5 5
Answer: Option A
19.
What will be the output of the program?
#include<stdio.h>
int main()
{
int i = 5;
while(i– >= 0)
printf(“%d,”, i);
i = 5;
printf(“\n”);
while(i– >= 0)
printf(“%i,”, i);
while(i– >= 0)
printf(“%d,”, i);
return 0;
}
A.
4, 3, 2, 1, 0, -1
4, 3, 2, 1, 0, -1
B.
5, 4, 3, 2, 1, 0
5, 4, 3, 2, 1, 0
C.
Error
D.
5, 4, 3, 2, 1, 0
5, 4, 3, 2, 1, 0
5, 4, 3, 2, 1, 0
Answer: Option A
Explanation:
Step 1: Initially the value of variable i is ‘5’.
Loop 1: while(i– >= 0) here i = 5, this statement becomes while(5– >= 0) Hence the while condition is satisfied and it prints ‘4’. (variable ‘i’ is decremented by ‘1’(one) in previous while condition)
Loop 2: while(i– >= 0) here i = 4, this statement becomes while(4– >= 0) Hence the while condition is satisfied and it prints ‘3’. (variable ‘i’ is decremented by ‘1’(one) in previous while condition)
Loop 3: while(i– >= 0) here i = 3, this statement becomes while(3– >= 0) Hence the while condition is satisfied and it prints ‘2’. (variable ‘i’ is decremented by ‘1’(one) in previous while condition)
Loop 4: while(i– >= 0) here i = 2, this statement becomes while(2– >= 0) Hence the while condition is satisfied and it prints ‘1’. (variable ‘i’ is decremented by ‘1’(one) in previous while condition)
Loop 5: while(i– >= 0) here i = 1, this statement becomes while(1– >= 0) Hence the while condition is satisfied and it prints ‘0’. (variable ‘i’ is decremented by ‘1’(one) in previous while condition)
Loop 6: while(i– >= 0) here i = 0, this statement becomes while(0– >= 0) Hence the while condition is satisfied and it prints ‘-1’. (variable ‘i’ is decremented by ‘1’(one) in previous while condition)
Loop 7: while(i– >= 0) here i = -1, this statement becomes while(-1– >= 0) Hence the while condition is not satisfied and loop exits.
The output of first while loop is 4,3,2,1,0,-1
Step 2: Then the value of variable i is initialized to ‘5’ Then it prints a new line character(\n).
See the above Loop 1 to Loop 7 .
The output of second while loop is 4,3,2,1,0,-1
Step 3: The third while loop, while(i– >= 0) here i = -1(because the variable ‘i’ is decremented to ‘-1’ by previous while loop and it never initialized.). This statement becomes while(-1– >= 0) Hence the while condition is not satisfied and loop exits.
Hence the output of the program is
4,3,2,1,0,-1
4,3,2,1,0,-1
20.
What will be the output of the program?
#include<stdio.h>
int main()
{
int i=3;
switch(i)
{
case 1:
printf(“Hello\n”);
case 2:
printf(“Hi\n”);
case 3:
continue;
default:
printf(“Bye\n”);
}
return 0;
}
A. Error: Misplaced continue
B. Bye
C. No output
D. Hello Hi
Answer: Option A
Explanation:
The keyword continue cannot be used in switch case. It must be used in for or while or do while loop. If there is any looping statement in switch case then we can use continue.
